fix(hash): 修复哈希处理部分资源处理问题

This commit is contained in:
tangge233
2026-02-22 22:41:30 +08:00
parent 73bdc53309
commit 4c1578f9aa
+50 -43
View File
@@ -1075,15 +1075,16 @@ Public Module ModBase
Re:
Try
'获取 MD5
Dim Result As New StringBuilder()
Dim File As New FileStream(FilePath, FileMode.Open, FileAccess.Read, FileShare.ReadWrite)
Dim MD5 As MD5 = New MD5CryptoServiceProvider()
Dim Retval As Byte() = MD5.ComputeHash(File)
File.Close()
For i = 0 To Retval.Length - 1
Result.Append(Retval(i).ToString("x2"))
Next
Return Result.ToString
Using h = MD5Cng.Create()
Dim Retval As Byte() = h.ComputeHash(File)
Dim Result As New StringBuilder(Retval.Length * 2)
For i = 0 To Retval.Length - 1
Result.Append(Retval(i).ToString("x2"))
Next
Return Result.ToString
End Using
Catch ex As Exception
If Retry OrElse TypeOf ex Is FileNotFoundException Then
Log(ex, "获取文件 MD5 失败:" & FilePath)
@@ -1106,15 +1107,17 @@ Re:
''检测该文件是否在下载中,若在下载则放弃检测
'If IgnoreOnDownloading AndAlso NetManage.Files.ContainsKey(FilePath) AndAlso NetManage.Files(FilePath).State <= NetState.Merge Then Return ""
'获取 SHA512
Dim file As New FileStream(FilePath, FileMode.Open, FileAccess.Read, FileShare.ReadWrite)
Dim sha512 As SHA512 = New SHA512CryptoServiceProvider()
Dim retval As Byte() = sha512.ComputeHash(file)
file.Close()
Dim Result As New StringBuilder()
For i As Integer = 0 To retval.Length - 1
Result.Append(retval(i).ToString("x2"))
Next
Return Result.ToString
Using file As New FileStream(FilePath, FileMode.Open, FileAccess.Read, FileShare.ReadWrite)
Using h = SHA512Cng.Create()
Dim retval As Byte() = h.ComputeHash(file)
Dim Result As New StringBuilder(retval.Length * 2)
For i As Integer = 0 To retval.Length - 1
Result.Append(retval(i).ToString("x2"))
Next
Return Result.ToString
End Using
End Using
Catch ex As Exception
If Retry OrElse TypeOf ex Is FileNotFoundException Then
Log(ex, "获取文件 SHA512 失败:" & FilePath)
@@ -1137,15 +1140,17 @@ Re:
''检测该文件是否在下载中,若在下载则放弃检测
'If IgnoreOnDownloading AndAlso NetManage.Files.ContainsKey(FilePath) AndAlso NetManage.Files(FilePath).State <= NetState.Merge Then Return ""
'获取 SHA256
Dim file As New FileStream(FilePath, FileMode.Open, FileAccess.Read, FileShare.ReadWrite)
Dim sha256 As SHA256 = New SHA256CryptoServiceProvider()
Dim retval As Byte() = sha256.ComputeHash(file)
file.Close()
Dim Result As New StringBuilder()
For i As Integer = 0 To retval.Length - 1
Result.Append(retval(i).ToString("x2"))
Next
Return Result.ToString
Using file As New FileStream(FilePath, FileMode.Open, FileAccess.Read, FileShare.ReadWrite)
Using h = SHA256Cng.Create()
Dim retval As Byte() = h.ComputeHash(file)
Dim Result As New StringBuilder(retval.Length * 2)
For i As Integer = 0 To retval.Length - 1
Result.Append(retval(i).ToString("x2"))
Next
Return Result.ToString()
End Using
End Using
Catch ex As Exception
If Retry OrElse TypeOf ex Is FileNotFoundException Then
Log(ex, "获取文件 SHA256 失败:" & FilePath)
@@ -1166,15 +1171,17 @@ Re:
Re:
Try
'获取 SHA1
Dim file As New FileStream(FilePath, FileMode.Open, FileAccess.Read, FileShare.ReadWrite)
Dim sha1 As SHA1 = New SHA1CryptoServiceProvider()
Dim retval As Byte() = sha1.ComputeHash(file)
file.Close()
Dim Result As New StringBuilder()
For i As Integer = 0 To retval.Length - 1
Result.Append(retval(i).ToString("x2"))
Next
Return Result.ToString
Using file As New FileStream(FilePath, FileMode.Open, FileAccess.Read, FileShare.ReadWrite)
Using h = SHA1Cng.Create()
Dim retval As Byte() = h.ComputeHash(file)
Dim Result As New StringBuilder(retval.Length * 2)
For i As Integer = 0 To retval.Length - 1
Result.Append(retval(i).ToString("x2"))
Next
Return Result.ToString
End Using
End Using
Catch ex As Exception
If Retry OrElse TypeOf ex Is FileNotFoundException Then
Log(ex, "获取文件 SHA1 失败:" & FilePath)
@@ -1647,14 +1654,14 @@ RetryDir:
''' 获取字符串 MD5。
''' </summary>
Public Function GetStringMD5(Str As String) As String
Dim md5Hasher As New MD5CryptoServiceProvider
Dim hashedDataBytes As Byte()
hashedDataBytes = md5Hasher.ComputeHash(Encoding.GetEncoding("gb2312").GetBytes(Str))
Dim tmp As New StringBuilder()
For Each i As Byte In hashedDataBytes
tmp.Append(i.ToString("x2"))
Next
Return tmp.ToString()
Using h = MD5Cng.Create()
Dim hashedDataBytes = h.ComputeHash(Encoding.GetEncoding("gb2312").GetBytes(Str))
Dim tmp As New StringBuilder(hashedDataBytes.Length * 2)
For Each i As Byte In hashedDataBytes
tmp.Append(i.ToString("x2"))
Next
Return tmp.ToString()
End Using
End Function
''' <summary>
''' 检查字符串中的字符是否均为 ASCII 字符。